2y^2/3-y-3=0

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Solution for 2y^2/3-y-3=0 equation: 


y in (-oo:+oo)

(2*y^2)/3-y-3 = 0

2/3*y^2-y-3 = 0

DELTA = (-1)^2-(-3*2/3*4)

DELTA = 9

DELTA > 0

y = (9^(1/2)+1)/(2/3*2) or y = (1-9^(1/2))/(2/3*2)

y = 3 or y = -3/2

y in { -3/2, 3 }

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